分析：根據(jù)題意分析得出：本題主要考查考生的字符串指針或字符串?dāng)?shù)組以及根據(jù)公式進(jìn)字符的ASCII值運算，再根據(jù)運算結(jié)果和條件進(jìn)行相應(yīng)的替代操作，要求考生僅編寫函數(shù)encryptChar()實現(xiàn)轉(zhuǎn)換功能。其中輸入及輸出函數(shù)給出且已調(diào)用，考生不必自己編寫。��

　　編寫函數(shù)encryptChar()的程序內(nèi)容如下：��

　　void encryptChar()��

　　{�� int i, j, val ;�オ�

　　for(i=0 ; i

　　for(j=0 ; j

　　val=(xx[i][j]*11) % 256 ;��

　　if(! (val<=32 || val>130)) xx[i][j]=val ;��

　　}��

　　}��

　　數(shù)據(jù)文件IN.DAT內(nèi)容如下：��

　　You may WANT A FIELD in field in each record to uniquely identify that1234��

　　record from all other records IN THE FILE. For example, the Employee123456��

　　Number field is unique if you DO NOT ASSIGN the same number to two12345678��

　　different employees, and you never reassign THESE NUMBERS to other12345678��

　　employees. If you wish to FIND OR MODIFY the record belonging to a11111111��

　　specific employee, this unique FIELD SAVES the thouble of determining22222��

　　whether you have the correct record.12345678901234567��

　　If you do not have a unique field, YOU MUST FIND THE first record123456787��

　　the matches your key and determine whether THEN RECORD is the one you33333��

　　want. If it is not the CORRECT ONE, you must search again to find others.4��

　　結(jié)果文件OUT.DAT內(nèi)容如下：��

　　You��m+3��WAZT�嗀�﨔#EDD��in��biWlL��in��W+Ax��rWAorL��to��uniquWl3��iLWntib3��tx+t1&1<��rWAorL��brom��+ll��otxWr��rWAorLs��#Z��THE�﨔#DE.�﨔or��W(+mplW,��txW�﨓mplo3WW1&1